在某些情况下熟悉SQL Server 通配符的使用可以帮助我们简单的解决很多问题。

 

--使用_运算符查找Person表中以an结尾的三字母名字

USEAdventureWorks2012;

GO

SELECT FirstName, LastName

FROM Person.Person

WHERE FirstName LIKE'_an'

ORDER BY FirstName;

 

---使用[^]运算符在Contact表中查找所有名字以Al开头且第三个字母不是字母a的人

USEAdventureWorks2012;

GO

SELECT FirstName, LastName

FROM Person.Person

WHERE FirstName LIKE'Al[^a]%'

ORDER BY FirstName;

 

---使用[]运算符查找其地址中有四位邮政编码的所有Adventure Works雇员的ID和姓名

USEAdventureWorks2012;

GO

SELECT e.BusinessEntityID, p.FirstName, p.LastName, a.PostalCode

FROMHumanResources.EmployeeAS e

INNER JOIN Person.PersonAS pON e.BusinessEntityID= p.BusinessEntityID

INNER JOIN Person.BusinessEntityAddressAS eaON e.BusinessEntityID=ea.BusinessEntityID

INNER JOIN Person.AddressAS aON a.AddressID= ea.AddressID

WHERE a.PostalCodeLIKE'[0-9][0-9][0-9][0-9]';

 

结果集:

EmployeeID FirstName LastName PostalCode

---------- --------- --------- ----------
290 Lynn Tsoflias 3000

 

--将一张表中名字为中英文的区分出来

create table tb(namenvarchar(20))

 

insert into tbvalues('kevin')

insert into tbvalues('kevin')

insert into tbvalues('')

 

select *,'Eng'from tbwherepatindex('%[a-z]%',name)>0and(patindex('%[-]%',name)=0)

union all

select *,'CN'from tbwherepatindex('%[-]%',name)>0andpatindex('%[a-z]%',name)=0

union all

select *,'Eng&CN'from tbwhere(patindex('%[-]%',name)>0)andpatindex('%[a-z]%',name)>0

 

结果集:

name

-------------------- ------

kevin Eng

CN

kevin Eng&CN

 

(3 row(s) affected)